String Reversal in JAVA with O(n * log(n))

A normal String Reversal program may take a brute force method with O(n). But with the help of recursion we can reduce the complexity, making it as O(n* log(n)).

Input: mahabaleshwar

Output: rawhselabaham

public class StringUtility{

     public static String getReverse(String in){
           int length = s.length();
           if(length <= 1)
              return in;
           String leftSubStr = in.substring(0, length / 2);
           String rightSubStr = in.substring(length / 2, length );

           return getReverse(rightSubStr) + getReverse(leftSubStr);